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Fermat's Lastish Crescent
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There is a proposition that Alperton to Mornington Crescent can be achieved in four moves. However proof has not been accepted for the existance of this number.
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[CdM] Well, I've got 347 stations in my database including N.L.L. and ghosts - and that doesn't yet have the old Met line stations to Brill - nor the Southend branch, nor some of the old District line stations. Memo: Must update database ! : So say there are 380 stations all told - then as you say, as (M=0) = Alperton by definition, and (M=4) = M.Cresc, again by definition, then we only need to calculate M1,M2 and M3 i.e. 380 x 379 x 378, just 54,439,560 possible combinations. But of course that is without taking into account LV, token placings, Becks variance, Transient moduli etc. etc. It would be naïve in the extreme to think that the four-station solution would work under just any old set of initial conditions. So, let's hypothesise that about 0.1% of possible initial condition combinations will allow the required result then the figure of 54 million needs multiply be 1000 to 54 billion. This may take a bit of processing after all - as the initial conditions will have to be set up each time. I think we're back to skill, I'm afraid.
The more calculations are carried out I am sure it will end up staring us in the face. I have been struck by the elegant simpicity of a the General Theory of Relevance: where e=mc2.( e being Euston)
I disagree with this in one aspect and the is the appropriatness of the mc2 given the Euston conflagration. The more sensible move and theory is e2=mc, (e being Euston Square) thus avoiding inverse coefficient of the magnetic modulus of previous BR station.
This brings me neatly to what may to some be a moment of de jvu. I question at this stage about Alperton as a first move and propose the usage of

rabmc2

where
r=Ravenscourt Park: a=Alperton: b=Blackhorse Road : with the 2on the diagonal being Euston Square. Geometrically this three sided quadrilateral could work in parallell to a divergence of LV on the Jubilee Line.

I proved all this ages ago with a Fronsky diagram drawn on a napkin. It was far too trivial for me to bother reproducing it here.
Maybe I overlooked that napkin... I was wondering where I heard this could be done. I have a feeling Bank maybe involved somewhere...
Ahh! a most interesting poser

I suspect that Kilydd could be on the right track. The e=mc² seems to be the signal in this discussion. Change it to e=(mc)² and a whole new, previously unseen, network appears. Of course, the square root of (mc) is still unkown, the history of (mc) having been hidden in the depths of iniquity for time untold - plus - what "e" equates to is also a problem.

The referent "e" could be, as stated, a local station (or somewhere on the projected line) but it could also be the symbol for Euclid. This raises very deep and meaningful questions. Like other governmental organisations, the word "TIME" enters the equation - as indeed both Einstein and Euclid intended. Anyway, unlike rab with his Sinclair I am about to bring into the endeavour my whiz-bang VIC20 super computer; unlike rab's ancient device, this has at least twice the power... a bit like ticket inspectors really. Please check in occasionally as it should take no more than twenty years to bring this conundrum to its final conclusion.
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